Re: Default array base index

On Jan 27, 11:36 am, "Dmitry A. Kazakov" <mail...@xxxxxxxxxxxxxxxxx>
wrote:
Actually both statements are wrong. As an example consider:

Foo : array (Character) of Boo;

Here the base index is neither specified nor 1. It is NUL (character).

Hmm, I would say it is specified explicitly but indirectly, via the
definition of the base type.

However, it does appear that Ada culture leans toward the
use of 1 as a default (for example, the language numbers the
dimensions of the array from 1 in attribute expressions).

Maybe, when index is a signed integer type. But with modular integer types
0 as the lower bound looks quite natural. And for enumeration types the
issue makes no sense anyway.

Okay.

Thanks for the reply.

-- Scott
.

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