Re: plz help!!!

newB wrote: 
if i have
%eax 0x101
%ebx 0x102
%ecx 0x103
%edx 0x01
%esi 0x00
%edi 0x1038
%ebp 0x1036
%esp 0x1032

what would this to be?
movw %ax, %bx


Since you are using the % I assume that you are using the AT&T syntax, so that would put the lower 16 bits of eax into the lower 16 bits of
ebx, which would make ebx = 0x103, since that value would fit into
the lower 16 bits and the upper 16 bits would all be 0 in both eax and
ebx before the instruction.

Masm and most Intel assemblers use Intel's syntax, which reverses
the operands in instructions.

mov R1, R2
is the same as
R1 = R2

But with the AT&T syntax it is like saying
move R1 into R2
which is
R2 = R1.

AT&T syntax is usually used on assemblers with UNIX like roots.

Nathan

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