Re: integer to characters

From: Default User (first.last_at_boeing.com.invalid)
Date: 10/23/03 

Date: Wed, 22 Oct 2003 23:40:52 GMT

Gene Wirchenko wrote:
>
> On Wed, 22 Oct 2003 22:38:24 GMT, Martin Ambuhl
> <mambuhl@earthlink.net> wrote:
>
> [snip]
>
> >int main(void)
> >{
> > int x[3] = { 123, 23, 3 };
> > char buf[BUFSIZ], *p;
> > size_t i;
> > for (i = 0; i < sizeof x / sizeof *x; i++) {
> ^^^^^^^^^
> What does this mean? I can not help but read it as the size of
> an int * *. I would have written "sizeof(int)".

How would you get a pointer to pointer from applying the dereferencing
operator to a pointer?
 
> Please explain as I am missing something if this is real code.

Yes, that divides the size of an entire array but the size of one
element, giving the number of elements in the array. Only works with
real arrays.

Brian Rodenborn

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