C++ Averager Exercise
From: TheFueley (thefueley_at_satx.rr.com)
Date: 06/23/04
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Date: 23 Jun 2004 12:32:58 -0700
Okay, I'm trying to make an averager type program. It should stop upon
user entering a non-numeric entry, and tally the average with whatever
is in the array already. Searching the list, i came across
cin.clear();
cin.ignore(INT_MAX, '\n');
that didn't work for me, I thought i could use break; to skip the loop
if an alpha is detected. It's not quite working the way I thought it
would. I got everything I need, except for the part about char input
stopping the loop correctly. Currently the program, upon entering a
char, will stop wherever its at and print the rest of the "Donation#4:
", "Donation#5: ", "Donation#6: ", etc. Then give a wrong average. I
know where the prob is, just not how to fix it. Here's what I've got.
/*Write a program that reads up to ten donation values into an array
of double. The program should terminate
* input on non-numeric input. It should report the average of the
numbers and also report how many numbers in the
* array are larger than the average.
*/
#include <iostream>
#include <cctype>
using namespace std;
const int Amount = 10;
double donations[Amount];
double average;
double total_donated = 0.0;
int greater_than_average = 0;
int main()
{
//get input
cout << "Enter up to " << Amount << " donations:\n";
for (int i=0; i<Amount; i++)
{
cout << "Donation #" << (i + 1) << ": ";
cin >> donations[i];
//stop if input is alpha
if (isdigit(donations[i]))
{
cin.clear();
cin.ignore(INT_MAX, '\n');
break;
}
}
//add up donations
for (int j=0; j<Amount; j++)
{
total_donated += donations[j];
}
//calculate average
average = total_donated / Amount;
cout << "The average donation was: " << average << "\n";
//find number of donations > average
for (int k=0; k<Amount; k++)
{
if (donations[k] > average)
greater_than_average += 1;
}
//display # of donations > average
cout << greater_than_average << " donations were higher than the
average.\n";
return 0;
}
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