overloading operator<<

From: Mark P (not_at_my.real.email)
Date: 10/29/04 

Date: Fri, 29 Oct 2004 13:28:05 -0700

If I want to be able to write:

cout << SomeClassObject;

then the model I've seen requires a declaration in the SomeClass defition:

friend ostream& operator<< (ostream& out, const SomeClass& obj);

Is there any other way to do this with operator<< defined as a member
function of SomeClass so that it would only require one argument?
Something like:

ostream& operator<< (ostream& out);

where of course the "this" parameter would take the place of "obj" in
the first declaration I displayed.

Relevant Pages

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  • Re: overloading operator<<
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    (alt.comp.lang.learn.c-cpp)