C program question

oasf2004_at_yahoo.com
Date: 10/30/04 

Date: 30 Oct 2004 13:57:47 -0700

Hi All,

One of the exercises of my C book ("C by Dissection" by Kelley and
Pohl) asked me to write a program that reads in an integer value for n
and then sums the integers from n to 2 * n if n is nonnegative, or
from 2 * n to n if n is negative. I think I was able to wrote
successfully the first part of the exercise, but I couldn't write the
second part. Please, see bellow the first part of my code:

#include <stdio.h>
 
int main()
{
    int n;

    printf("Input one integer: ");
    scanf("%d", &n);
    while (n >= 0)
        printf("The result is %d\n", n += (2 * n));
    
    return 0;
}

How could I write the second part of my code? I have no idea how could
I write a second while loop in order to get the sums from 2 * n to n,
if n is negative. I have tried:
...
while (n < 0) {
   printf("The result is %d\n", n -= (2 * n));
....
but of course I didn't get the correct answer.
Thanks in advance for any hint!
Hoffmann

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