Re: [Newbie] What is sizeof() ?

From: Christian Bau (christian.bau_at_cbau.freeserve.co.uk)
Date: 10/31/03 

Date: Fri, 31 Oct 2003 01:01:44 +0000

In article <11iob.922$eV1.240@newsfep1-gui.server.ntli.net>,
 "Peter Pichler" <pichlo6@pobox.sk> wrote:

> "Vincent Pierroux" <VPierroux@cybernet.be.SPAM> wrote in message
> news:3fa17e49$1_8@corp.newsgroups.com...
> > So, if it is a operator i don't have any argument push on the stack like a
> > function.
> >
> > If i make onething like that
> >
> > for(foo=0;foo<1000;i++)
> > foo+= sizeof myStruct ;
> >
> > it take the same processing time this
> >
> > var= sizeof myStruct
> > for(foo=0;foo<1000;i++)
> > foo+= var;
>
> Most likely the first one will take shorter: sizeof myStruct is a constant,
> so the compiler might just replace the whole loop with
>
> foo += 1000 * sizeof myStruct;
>
> On the other hand, so it could in the second case, should it be clever
> enough.

You mean stupid enough? Take a very good look at the for loop. It is
most likely _not_ executed 1000 times.

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