default expression type

From: j0mbolar (j0mbolar_at_engineer.com)
Date: 06/30/04 

Date: 30 Jun 2004 05:52:33 -0700

does the standard guarantee that the type of an expression
is implicitly void as it does for functions?

for example:

int i = 0xff;

    i;

does the type implicitly have void
since it isn't used for anything.