Re: small C puzzles
From: ByteSurfer (bytesurfer_at_gmail.com)
Date: 09/03/04
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Date: 2 Sep 2004 23:11:32 -0700
madhav_a_kelkar@hotmail.com wrote in message news:<338e571.0409010104.1f53512d@posting.google.com>...
> i was browsing this problem:
>
> The following is a piece of C code, whose intention was to print a
> minus sign 20 times. But you can notice that, it doesn't work.
>
> #include <stdio.h>
> int main()
> {
> int i;
> int n = 20;
> for( i = 0; i < n; i-- )
> printf("-");
> return 0;
> }
>
> Well fixing the above code is straight-forward. To make the problem
> interesting, you have to fix the above code, by changing exactly one
> character. There are three known solutions. See if you can get all
> those three.
>
>
> one solution is to use n-- instead of i--. please let me know the
> other two.
Sure it was obvious that the looping you do was always will decrement
by one so . how on earth will be the looping exit when all decrement
of 1 from zero will become more negative . so. just by letting the n
to be n-- will work.
if not you can think of putting the condition to be n<=i then the
updating you put the increment of n++ then surely at one time the the
n will bigger than the value i so it will be exiting the loop.
If not you can try this method. of putting negative in front of n or
even i.
But this was not that practical, cos it just will make your coding
more complicated. So, poosibly stick to the more simple alogarithm.
Regard,
ByteSurfer
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