How to parse a string like C program parse the command line string?

linzhenhua1205_at_163.com
Date: 03/12/05 

Date: 11 Mar 2005 21:26:57 -0800

I want to parse a string like C program parse the command line into
argc & argv[][].
I hope don't use the array the allocate a fix memory first, and don't
use the memory allocate function like malloc.
who can give me some ideas?
The following is my program, but it has some problem. I hope someone
would correct it.
////////////////////////////
//Test_ConvertArg.c
////////////////////////////
#include <stdio.h>
#include <string.h>

int ConvertArg(char* Str, char* Argv[])
{
        int Argc; // Count the argument).
        int Count = 0;
        int i = 0;
        char* StrPtr;
        char* TmpStrPtr;
        StrPtr = Str;

        for(; *StrPtr == ' ';) // ignore the whitespace before the
command!
        {
                ++StrPtr;
        }

        TmpStrPtr = StrPtr;

        for (Argc = 0; (*StrPtr) != '\n'; StrPtr++, Count++)
        {

                if(*StrPtr == ' ')
                {
// if exist multi whitespace together,
//argc just count once,and don't continually change argv!
                        if( *(StrPtr+1) == ' ')
                        {
                                Count--;
                                continue;
                        }
                }

                Count--;
// the following setences have problems.
                memcpy(Argv[Argc],TmpStrPtr,Count);

#if 0
                for(i=0; i <= Count; i++)
                {
                        Argv[Argc][i] = *TmpStrPtr;
                        TmpStrPtr++;
                }
#endif

                TmpStrPtr = StrPtr;
                i = 0;
                Argc++;
        }
}

int main(int argc, char* argv[])
{
        char** argv1;
        char* str = "";

        char** str1 = "test";
        char* str2 = " ";
        memcpy(str2, str1[0], 4);
        printf("%s\n", str2);
        // test ConvertStr()
        str = " a asdf ";
        argv1 = "";
        printf("argc = %d, argv0 = \n",ConvertArg(str, argv1));
        str = " a asdf";
        printf("argc = %d, argv0 = %s ,argv1 = %s\n",ConvertArg(str, argv1),
argv1[0], argv1[1]);
        str = " asdf asdf";
        printf("argc = %d, argv0 = %s ,argv1 = %s\n",ConvertArg(str, argv1),
argv1[0], argv1[1]);
        str = " asdf asdf";
        printf("argc = %d, argv0 = %s ,argv1 = %s, argv2 =
%s\n",ConvertArg(str, argv1), argv1[0], argv1[1], argv1[3]);
        return 1;
}

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