function pointers as function parameters

I am experimenting with function pointers. Unfortunately, my C book has nothing on function pointers as function parameters. I want to pass a pointer to ff() to f() with the result that f() prints the return value of ff(). The code below seems to work, but I would appreciate your comments. Have I got it right? Does the function name "decay" to a pointer?


#include <stdio.h>
/* declares a function which takes an argument
   that is a pointer to a function returning an int */
void f(int (*fptr)());
/* function returning an int */
int ff(void);

int main(void)
{
    f(ff); /* pass the address of ff to f */

    return 0;
}

void f(int (*fptr)())
{
    int a;
    a = (*fptr)(); /* deref the func pointer */
    printf("%d\n", a);
    return;
}

int ff(void)
{
    return 2345;
}
.

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