Re: how to define a function pointer variable witout typdef?

Keith Thompson wrote: 
Joe Wright <joewwright@xxxxxxxxxxx> writes:

Keith Thompson wrote: 

[snip]

Typedefs are a bit odd in that a typedef doesn't actually create a
new type, merely an alias for an existing type.  But a typedef is a
definition because the thing it creates is the alias, not the type.
And now we wait for the experts to point out my errors.


I suppose a typedef is not a definition. This because it does not
create an object in memory. It's another case of C overloading the
English language. Odd, isn't it that '#define X 2' is not a definition
either.



No, it doesn't create an object in memory.  Neither does a function
definition.  A definition, as I understand it, is a declaration that
creates the named entity, rather than merely referring to an entity
that's created elsewhere.  The entity doesn't have to be an object.


Nice side step. In what way is a typedef a declaration creating a named entity?

--
Joe Wright                            mailto:joewwright@xxxxxxxxxxx
"Everything should be made as simple as possible, but not simpler."
                    --- Albert Einstein ---
.

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