Re: multidimensional arrays and pointers

> what is the difference between,


> (arr + 1) and

this gives you the address of the second element in the array. It's the
same as: &(arr[1])

> *(arr + 1)

This gives you the insides of the second element in the array. It's the
same as: arr[1]

You could also do like this:
*(*(arr + 1) + 1)

This should return 'e'. This is the same as: arr[1][1]

--
bjrnove

.

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