Re: why is it so ?

"S.Tobias" <siXtY@xxxxxxxxxxxxxxxxxxxxxxxxxx> writes:

> Robert Gamble <rgamble99@xxxxxxxxx> wrote:
> > S.Tobias wrote:
>
> >> a[i] = one(0 || i++);
>
> > Still has the possibility for undefined behavior, the "0 || i++" could
> > be evaluated followed by i in "a[i]" before the function is called
> > without an intervening sequence point.
>
> I think it can be evaluated in one of the two ways:
>
> (lhs, rhs)
> a[i] , 0 [SEQP] i++ [SEQP] one() , return 1 [SEQP] =
>
> or:
>
> (rhs, lhs)
> 0 [SEQP] i++ [SEQP] one() , return 1 [SEQP] a[i] , =

You missed at least one way:

0 [SEQP] a[i] , i++ [SEQP] one() , return 1 [SEQP] =

This ordering shows how this statement could evoke undefined behavior.
.

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