Re: dynamically allocating a 2d array

Stick to the following rule:
-Generally, an array name in an expression is evaluated as a pointer to
its first element.

Thus,
int array[Y][X] is a 2d array, an array of Y arrays of X integers.
You can write its dynamic counterpart as follows:
int (*array)[X] which is a pointer to an array of X integers.
And then allocate it dynamically via malloc:
array = malloc(sizeof(*array) * Y );

.

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