Re: Problem with printf formats

Guenther Sohler wrote:
>

I have following code:

int main(void)
{
	printf("%.3lf\n",-2158470*0.001);
}

it prints

-2158.470

How can i disable '0' at the end, if they are not needed ?

Is there a possibility just to write %lf and just print as many
digits as needed to represent the number ?

You are asking the wrong question. The trailing zero is needed to represent the number. Otherwise how could you distinguish it from:

    printf("%.2f\n", -2158471 * 0.001)

(always assuming that -2158471 does not create an overflow)

Your question, I believe, is "how to suppress trailing zeroes". A little thought and an intermediary buffer should give you a suitable answer for that.

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