Re: Allocation of memory for Array of Pointers

i wrote:
> Forgot to mention that u must typecast the calloc function as its
> return type is void * (however some compiler automatically return
> pointer type of the type_of_its_second_ argument.)

i am sorry for the silly abbreviations, i had used. Thanks, for the
advice.

Martin Ambuhl wrote:
>Pay no attention to chandon; he knows nothing.

I never told that i know everything. i am a beginner to C and, really,
i don't know anything, as such, about C. I got my first lesson and I am
eager to learn more.

Keith wrote:
>No. calloc() returns a result of type void*, but it's implicitly
>converted to the target pointer type. An explicit cast is unnecessary
>and can mask errors (such as forgetting the required "#include <stdlib.h>"
>or compiling C code with a C++ compiler).

In my case, i was trying to compile this code with a C++ compiler. But,
please, can you elaborate how it masks the error and how stdlib.h helps
in conversion of type void * to target pointer type? i mean, how it
determines the target pointer type, if i am using a C compiler.

.

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