Re: The void** pointer breaking symmetry?
elmar@xxxxxxxxxx writes:
char *cp;
void *vp;
void **vpp;
// 1
cp=vp;
// 2
cp=*vpp;
Why is the first instruction allowed while the second one creates a
compiler warning/error?
Both are allowed. If the compiler refuses to allow one of them
(possibly with a warning) then you are probably using a C++
compiler.
--
"Your correction is 100% correct and 0% helpful. Well done!"
--Richard Heathfield
.
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(comp.lang.cpp) |
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