Re: Array and Pointer Tutorial


You have not followed the suggested practice of using sizeof *pointer
being assigned to. Your example should have been:
#include <stdlib.h>

int main(void) {
int array[5];

int *q = malloc(sizeof *q);

return 0;
}

Or, if you want array and q to always be the same type, you could have used:
#include <stdlib.h>
int main(void) {
int array[5], *q = malloc(sizeof *q);

return 0;
}

I really can't see why you would think of using sizeof some other object.
--
Flash Gordon, living in interesting times.
Web site - http://home.flash-gordon.me.uk/
comp.lang.c posting guidelines and intro:
http://clc-wiki.net/wiki/Intro_to_clc

Inviato da X-Privat.Org - Registrazione gratuita http://www.x-privat.org/join.php

I can't really put me pinpoint the exact part, but I know I'm missing
some kind of underlying concept when I see the construction:

int *q = malloc(sizeof *q);

Maybe when I'm scrubbing the dairy coolers at work tomorrow morning,
the exact part that is irking me will set in. Then I can come back and
ask the EXACT question about the construction.

Chad

.

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