Re: Linked list, no out put,help

* asm_fool@xxxxxxxxxxx:
dear group,

/*Linked list in C*/


#include<stdio.h>
#include<stdlib.h>

struct node
{
int data;
struct node *next;
}a;

void init(int data)
{
struct node *p;
p = malloc(sizeof *p);
if(!p)
{
printf("mem error");
exit(EXIT_FAILURE);
}

a.data = data;
a.next = NULL;
p = &a;
}

int main(void)
{
unsigned int i,j;
for(j=0;j<6;j++)
{
scanf("%d",&i);
init(i);
}
while(a.next != NULL)
{
for(j=0;j<6;j++)
printf("value = %d\n",a.data);

}
return 0;
}

This is not the first time I am implementing a linked list.But every
time I
try to do that I get no out put. The above is the same situation. The
above
don't print any out put. Can any one tell me why.

In your 'init' function you set 'a.next = NULL'. The continuation condition for your output loop is 'a.next != NULL'. That condition evaluates to 0 the first time, and the loop body is never executed.


[OT]
I can not configure news reader in my company. Same with the mail
reader. Though I use win98 the pop and nntp server simply functioning.
So I go for the ugly google. [/OT]

Do you actually work in a company? This is not professional code. It's student code.

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
.

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