Re: a^=(b^=a); ?

Clark S. Cox III wrote:
Thomas J. Gritzan wrote:
Clark S. Cox III schrieb:
Robert Gamble wrote:
Clark S. Cox III wrote:
a^=(b^=a)

is undefined; period.
How do you figure that?
It modifies 'a' and it evaluates a for a reason other than determining
it's new value in between sequence points.

Wouldn't then with

a = a; and
node = node->next;

be undefined, too?

(with a of type int and node a linked list structure pointer)


After writing a long defense of my position, I come to realize that
a^=(b^=a) might not be undefined.

I agree with ena8t8si that this is well-defined although the meaning of
the clause you cite could be better spelled out in the Standard.

Robert Gamble

.

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