Re: Cannot return values of char variable

Pedro Pinto wrote:
>
>
> I can do that inside main. What i can't do is with divide:
>
> char divide(char search_string[], char *array[], char *delimiter)
>
> and return the string you printed! Can this be done?
>

As I understand, you want to create the array which holds the divided
tokens inside divide function and return it (instead of passing
char *array[] as argument). Please find below the code which does that.

Please note that this is my first answer to a question here.
So I would suggest you to wait, for any responses from the more
experienced members of c.l.c.

Also after posting my previous testcase, i have noticed few issues in
it. This version is better (I guess).


#include <stdio.h>
#include <string.h>
#include <stdlib.h>

char **divide(char search_string[], char *delimiter){
int loop;
char **array = malloc(50 * sizeof(char *));
array[0]=strtok(search_string,delimiter);

if(array[0]==NULL)
{
printf("No test to search.\n");
exit(0);
}

for(loop=1;loop<50;loop++)
{
array[loop]=strtok(NULL,delimiter);

if(array[loop]==NULL)
return array;
}

return array;
}

int main(void) {
int i = 0 ;
char **arr;

char input[] ="this,is,comma,separated,string";

arr = divide(input, ",");

printf("Divided contents\n");
for(i = 0; i < 50; i++)
{
if(arr[i]==NULL)
break;

printf("%s \n", arr[i]);
}

free(arr);
return 0;
}

Hope this helps.

--
Prasad

.

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