Re: pointers and array of pointers

Klarth wrote:

I often think of pointers as a VARIABLE that contains a reference
to an address. So when you are calling myswap, you are passing in
copies of the references. Want you want to do in myswap is pass the
pointers by reference so you can change it. You do this by passing
in type char ** and passing the address of the pointers instead. In
myswap2, you are already effectively passing by reference, which is
why the swap is reflected when it returns.

What, if anything, does this mean? See below.

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