Re: Void function returns value
André Gillibert wrote:
Keith Thompson wrote:
If the function name is the operand of a unary "&", the implicit
conversion does not take place, so ``&foo'', like ``foo'' yields the
address of the function.
``&foo'' and ``foo'' are equivalent; neither
calls the function. ``&foo()'' and ``foo()'' are equivalent; both
call the function.
No. &foo() is equivalent to &(foo()) which is a constraint violation.
He must have meant ((&foo)()).
--
pete
.
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(comp.lang.c) |
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