Re: printf("%d",float)

candy_init@xxxxxxxxx said:

Hi all,
I just came across the following program:

#include <stdio.h>
int main()
{
float a = 12.5;
printf("%d\n", a);
printf("%d\n", *(int *)&a);
return 0;
}

The program prints 0 and 1095237362. However, in my opinion it should
print 12 at both the places. Can anybody tell me where I am wrong?

You are wrong in thinking that %d is the appropriate format specifier for a
float, and you are wrong in thinking that you can meaningfully cast the
address of a float into the address of an int.

--
Richard Heathfield <http://www.cpax.org.uk>
Email: -http://www. +rjh@
Google users: <http://www.cpax.org.uk/prg/writings/googly.php>
"Usenet is a strange place" - dmr 29 July 1999
.

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