Re: Meaning of memset (Was: Re: Assigning values to char arrays)

pete wrote:
<snip>

No. unsigned char may not have padding bits.
Is this "just a theory"?
No.

N869
5.2.4.2.1 Sizes of integer types <limits.h>

[#2] The value UCHAR_MAX+1
shall equal 2 raised to the power CHAR_BIT.

Thanks to adding to my confusion :)
So I have an 11-bit machine bytes

That's what "CHAR_BIT equals eleven" means.

Sorry for being that stubborn, but:
Why?
Why can't I have CHAR_BIT==8 on a 11-bit machine?
E.g. my int would be something like say 11(lower)+8(upper)=19 bits.
Is it postulated somewhere that
UINT_MAX+1==(UCHAR_MAX+1)*sizeof(unsigned)
?
I don't think so.
.

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