Re: typedef function with void parameters

William Xu wrote:

This won't compile:

,----
| int foo(char *p)
| {}
|
| int main(int argc, char *argv[])
| {
| typedef int (*FUNC)(void *);
|
| FUNC f = foo;
| }
`----

The error is:

,----
| gcc -O2 /Users/william/studio/helloworlds/foo.cpp -lm -o foo
| /Users/william/studio/helloworlds/foo.cpp: In function 'int main(int, char**)':
| /Users/william/studio/helloworlds/foo.cpp:26: error: invalid conversion from 'int (*)(char*)' to 'int (*)(void*)'
`----

So, which do you want -- a function taking a `void*` or a function taking
a `char*`? They're not compatible types. Pick one.

--
Chris "can't fit a quart into a magnetic pot" Dollin

Hewlett-Packard Limited registered office: Cain Road, Bracknell,
registered no: 690597 England Berks RG12 1HN

.

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