Re: small string question

"Bill Cunningham" <nospam@xxxxxxxxx> wrote in comp.lang.c:

As I have been studing my tutorial I came up with this question. I
took char passw(char name[]);


In C, you can't pass an array by value. The language's misleading syntax, however, would have you believe that you can. The following three functions are identical:

void Func(char *name) { *name = 0; name = 0; }
void Func(char name[]) { *name = 0; name = 0; }
void Func(char name[72]) { *name = 0; name = 0 }

In the third one, 72 is ignored. All you've got is a non-const pointer in all three cases


and initialied this function in a header with other includes for
standard library headers.


We declare a function in a header file, and define it in a source file. Another name for a declaration is a "prototype". I've never see people use the word "initialiser" though in referring to a function declaration. Here's what an initialiser is in C:

int arr[5] = {7,3,2,3,4};


This doesn't seem to work so is what I want
this?

char passw(char *name);


This is no different from your previous declaration.


I haven't got to pointers in the tutorial and I'm taking my time. But
in this particualr function should it be initialized with a pointer?
Does char *name; equal char name[] ?


Sorry I'm not sure what you're asking.

--
Tomás Ó hÉilidhe
.

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