Re: Declared global variable isn't being seen by main.

changed to the following:

printf("Record %lu wrong length:%llu Should be %d
\n",record,cur_len,giv_len);

to no avail


On Mar 13, 8:32 pm, Lew Pitcher <lpitc...@xxxxxxxxxxxx> wrote:
Tristin.Co...@xxxxxxxxx wrote:
Can someone tell me why giv_len isn't being seen in this statement
below "printf("Record %d wrong length:%d Should be %d
\n",record,cur_len,giv_len)"

The answer is "because you lied to printf() by telling it that the cur_len
variable was an int".

Correct your printf() statement format string to reflect the fact that the
second variable value is an unsigned long long, and your problem should go
away.



=cut

#include <stdio.h>
#include <stdlib.h>

char delimiter = '\n';
unsigned long long int cur_len = 0L;
int giv_len;
unsigned long int record = 0L;

int main(int argc, char *argv[])
{
char* infile = argv[1];
char* outfile = argv[2];
giv_len = atoi(argv[3]);
printf("giv_len is :%d\n",giv_len);

FILE* i = fopen(infile,"r");
FILE* o = fopen(outfile,"w");
int ch;
while((ch=fgetc(i) ) != EOF) {
++cur_len;

if(ch == delimiter) {
++record;
/*printf("%d\n",cur_len); */
if(cur_len != giv_len) {
printf("Record %d wrong length:%d Should be %d
\n",record,cur_len,giv_len);
fprintf(o,"Record %d wrong length:%d\n",record,cur_len);
}
cur_len=0;
}
}
fclose(i);
fclose(o);

return 0;
}

--
Lew Pitcher

Master Codewright & JOAT-in-training | Registered Linux User #112576http://pitcher.digitalfreehold.ca/ | GPG public key available by request
---------- Slackware - Because I know what I'm doing. ------

.

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