Re: Declared global variable isn't being seen by main.

I think i figured it out. I'm on a windows box(using minGW). maybe it
doesn't support long long b/c when i change it to just unsigned long
and change the format accordingly, it works.

Any way I can work around this and get the long long?


On Mar 13, 8:40 pm, Tristin.Co...@xxxxxxxxx wrote:
changed to the following:

printf("Record %lu wrong length:%llu Should be %d
\n",record,cur_len,giv_len);

to no avail

On Mar 13, 8:32 pm, Lew Pitcher <lpitc...@xxxxxxxxxxxx> wrote:

Tristin.Co...@xxxxxxxxx wrote:
Can someone tell me why giv_len isn't being seen in this statement
below "printf("Record %d wrong length:%d Should be %d
\n",record,cur_len,giv_len)"

The answer is "because you lied to printf() by telling it that the cur_len
variable was an int".

Correct your printf() statement format string to reflect the fact that the
second variable value is an unsigned long long, and your problem should go
away.

=cut

#include <stdio.h>
#include <stdlib.h>

char delimiter = '\n';
unsigned long long int cur_len = 0L;
int giv_len;
unsigned long int record = 0L;

int main(int argc, char *argv[])
{
char* infile = argv[1];
char* outfile = argv[2];
giv_len = atoi(argv[3]);
printf("giv_len is :%d\n",giv_len);

FILE* i = fopen(infile,"r");
FILE* o = fopen(outfile,"w");
int ch;
while((ch=fgetc(i) ) != EOF) {
++cur_len;

if(ch == delimiter) {
++record;
/*printf("%d\n",cur_len); */
if(cur_len != giv_len) {
printf("Record %d wrong length:%d Should be %d
\n",record,cur_len,giv_len);
fprintf(o,"Record %d wrong length:%d\n",record,cur_len);
}
cur_len=0;
}
}
fclose(i);
fclose(o);

return 0;
}

--
Lew Pitcher

Master Codewright & JOAT-in-training | Registered Linux User #112576http://pitcher.digitalfreehold.ca/ | GPG public key available by request
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