Re: sizeof()'s strange behviour

Richard Heathfield <rjh@xxxxxxxxxxxxxxx> writes:
arnuld said:
[...]
printf("sizeof(%s): %d\n", s, sizeof(s));

...so we'd expect this to print 16 in place of the second % format
specifier. Note that your printf is misleading. It will print:

sizeof(Saurabh Nirkhey): 16

but in fact it's sizeof s that is 16.
[...]

Furthermore, "%d" causes printf to expect an int argument, but
sizeof(s) is of type size_t. It's likely to happen to work on systems
where int and size_t are the same size, but the right way is (with a
couple of other tweaks):

printf("sizeof s: %d\n", (int)sizeof s);

--
Keith Thompson (The_Other_Keith) <kst-u@xxxxxxx>
Nokia
"We must do something. This is something. Therefore, we must do this."
-- Antony Jay and Jonathan Lynn, "Yes Minister"
.

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