Re: Is cast operator unary or binary? How many operands?

I'd say one operator, the cast operator, and two operands: typename
and expression.

But everywhere I read, cast is categorized as an unary operator. Why
is that? Is it just a syntax cotegory?

(typename)(expression) has one operator `(typename)' and one operand
`(expression)'.
The reason the type is enclosed in parentheses (as a design decision)
is probably to avoid ambiguity, consider this:

int i = 1; /* define and initialize i to 1 */
{
int i; /* cast i to int, a statement with no effect, or define i in
block scope? */

}

Thanks, Vipps.

According to your answeer, the operator '(typename)' is very
particular, because it not a single token but three AND the middle
token is anything an identifier may be.

JM.
.

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