Re: taking a "word" as input

On 30 Apr, 23:02, arnuld <NoS...@xxxxxxxxxx> wrote:
.> On Tue, 29 Apr 2008 02:47:18 -0700,Nick Keighleywrote:

are all your words the same size?

It depends on the user, what he likes to input at run-time.

in other words, no.

santosh has pointed out some of the design drivers for this.
So decide do you want a fixed size (limits word size and wastes space)
or a variable size (harder to program).


If you use the array of pointers you'll have to get the memory
for each word from somewhere (eg. malloc())

Note Well


yes. I came up with this code and as you can see it does not do what I
want. I want to take every word into the input but it only takes 1st for
obvious reasons. I am not able to think of the way to take all the words
of the input:

1. after you read a word you need to skip to the next word.

eg. read until you get a letter

2. you need somewhere to store the words. Either a 2D array or
use malloc().


#include <stdio.h>
#include <ctype.h>

enum MAXSIZE { MAXWORD = 100 };

char *getword( char *, int );

int main(void) {

  char buffer[MAXWORD];

this only holds one word

char buffer[MAXNUMWORDS][MAXWORD];
OR char* buffer [MAXWORD]


  getword( buffer, MAXWORD );

pass the appropriate argument

<snip>

--
Nick keighley
.

Relevant Pages