Re: program bug


"Robert Gamble" <rgamble99@xxxxxxxxx> wrote in message
news:2d73e006-fc0d-4ed7-ae1e-43535dea6140@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx

Not a portable return value from main.

}
if (argv[1]=="b") {

This isn't doing what you think it is. This is comparing the address
of first program argument to the address of the string literal "b"

Was declaring b as a pointer to char proper? Or should a simple b of
type char all that's needed?


which will always be different. Either use (strcmp(argv[1], "b") ==
0) or say:

if (argv[1][0] == 'b') {

which will compare the first letter of the first argument to the
character constant b.

I do not understand the above but it looks like a good way to write
code. Why is a zero used as the second dimension of this array?

Bill



.

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