Re: Handling 'initializer element not constant' error

richard@xxxxxxxxxxxxxxx (Richard Tobin) writes:

In article <87abj1u4q4.fsf@xxxxxxxxxxxxxxxx>,
Ben Pfaff <blp@xxxxxxxxxxxxxxx> wrote:

The C standard recognises the problems with errno and doesn't require
it to be an identifier.

It's definitely an identifier.

Obviously "errno" is an identifier. I should have said that it's a
macro that doesn't have to expand to an identifier.

However, it might not be the name of a variable with external linkage.

It might not expand to the name of a variable at all.

Right. That's one way that it might not be the name of a
variable with external linkage.
--
char a[]="\n .CJacehknorstu";int putchar(int);int main(void){unsigned long b[]
={0x67dffdff,0x9aa9aa6a,0xa77ffda9,0x7da6aa6a,0xa67f6aaa,0xaa9aa9f6,0x11f6},*p
=b,i=24;for(;p+=!*p;*p/=4)switch(0[p]&3)case 0:{return 0;for(p--;i--;i--)case+
2:{i++;if(i)break;else default:continue;if(0)case 1:putchar(a[i&15]);break;}}}
.

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