Re: Function pointer array as parameter to a function

On May 20, 5:00 pm, vipps...@xxxxxxxxx wrote:
On May 20, 6:25 pm, Bart <b...@xxxxxxxxxx> wrote:

So what is the normal technique for a type specification to be
converted from declarative form to a cast?

The normal rule is just to write a declaration, remove the name and
the ; and enclose in ()s.  Do you have an example where this is wrong?

Functions, you need to add an extra asterisk (*), ie
int foo(int);
int (*)(int)> Now that I try to find an example, it's not so easy!

Probably there was no actual error, apart from actual errors of syntax
and odd things like this:

int ((*((*(x(char)))[]))[]);

Why the redundant parenthesis?
That's equivalent to int (*(*x(char))[])[], and what the function
returns is a pointer to an incomplete array of pointers to incomplete
arrays of int.
int y;

This a type error (the type returns a function). But decl was quite
happy with the cast when written without the 'char':

(int ((*((*(()))[]))[]))y

But gave a syntax error on: (int ((*((*((char)))[]))[]))y

So just funny things with cdecl.

It's funny things with your code, nod cdecl.

I don't know. If you have cdecl to hand (and it's like mine) try this:

cdecl explain (int (*(*(char))[])[])x

Gives "syntax error"

Now take out the char to leave (), no parameters:

cdecl explain (int (*(*())[])[])x

Gives "cast x into function returning pointer to array of pointer to
array of int"

Why the difference between a function with 0 params and a function
with 1 param? Both are illegal surely?

--
Bartc
.

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