Re: Address of an array = address of its 1st element: undecidable question ?

Richard Heathfield wrote:
CBFalconer said:
Peter Nilsson wrote:
Richard Heathfield <r...@xxxxxxxxxxxxxxx> wrote:

... snip ...

If you try to take the value of an array, what you
actually get is the value of a pointer to the first
member of the array. That doesn't mean that an array
is the same as a pointer. If you mean that &array
and &array[0] have the same value, they don't. They
have different types.

What about (void *) &array == (void *) &array[0]?

You should get "syntax error" or equivalent.

Why?

Woops - I read that as '=', not as '=='. Good catch.

--
[mail]: Chuck F (cbfalconer at maineline dot net)
[page]: <http://cbfalconer.home.att.net>
Try the download section.


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