Re: char**

From: MN <mazouz.nezhate@xxxxxxxxx>
Date: Sat, 30 Aug 2008 05:07:54 -0700 (PDT)

On Aug 30, 2:55 pm, Richard Heathfield <r...@xxxxxxxxxxxxxxx> wrote:

MN said:

I have a question :
How to understand the mean of char** type ?

char is a type - objects of that type are 1 byte in size and can contain as
their value any single member of the execution character set.

char * is a type - objects of that type are sizeof(char *) bytes in size,
and can contain as their value the address of a single char.

char ** is a type - objects of that type are sizeof(char **) bytes in size,
and can contain as their value the address of a single char *.

What is the question behind the question?

--
Richard Heathfield <http://www.cpax.org.uk>
Email: -http://www. +rjh@
Google users: <http://www.cpax.org.uk/prg/writings/googly.php>
"Usenet is a strange place" - dmr 29 July 1999

the question is :
I have a function which returns an array of chars with 2 dimensions.
The size of array is dynamically changed by malloc.
To return this array I must declare it as an extern in the header file
like this: extern char** array.
if I use extern char* array, I get error.
.

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References:
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  - From: Richard Heathfield

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