Re: char**
- From: pete <pfiland@xxxxxxxxxxxxxx>
- Date: Sat, 30 Aug 2008 08:22:38 -0400
MN wrote:
On Aug 30, 2:55 pm, Richard Heathfield <r...@xxxxxxxxxxxxxxx> wrote:MN said:
I have a question :char is a type - objects of that type are 1 byte in size and can contain as
How to understand the mean of char** type ?
their value any single member of the execution character set.
char * is a type - objects of that type are sizeof(char *) bytes in size,
and can contain as their value the address of a single char.
char ** is a type - objects of that type are sizeof(char **) bytes in size,
and can contain as their value the address of a single char *.
What is the question behind the question?
--
Richard Heathfield <http://www.cpax.org.uk>
Email: -http://www. +rjh@
Google users: <http://www.cpax.org.uk/prg/writings/googly.php>
"Usenet is a strange place" - dmr 29 July 1999
the question is :
I have a function which returns an array of chars with 2 dimensions.
The size of array is dynamically changed by malloc.
I don't understand what you mean.
Does your function create the array
and then the calling function changes the size of the array,
or
does your function receive the address of an array as a argument
and then change the size of it?
To return this array I must declare it as an extern in the header file
like this: extern char** array.
if I use extern char* array, I get error.
--
pete
.
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