Re: a question abou "atoi"

66650755@xxxxxx wrote:
First,thanks for all who have answered my last question.

if char string[20]="12345";

how could I convert the string[2](that is "3") to an int by using
atoi?

You don't need to - string[2] is already an integer type.

int x = string[2];

does the trick.

int a;
char string[7]="111111";

a=atoi(string[3]);

atoi takes a string, string[2] is a character - which is an integer type.

error C2664: 'atoi' : cannot convert parameter 1 from 'char' to 'const
char *'
Conversion from integral type to pointer type requires
reinterpret_cast, C-style cast or function-style cast.

You're using a C++ compiler, don't do that if you're compiling C, the two languages are different.
.

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