Re: Arrays as function parameters and sizeof()

Andreas Eibach wrote:
[... sizeof function parameter declared as array ...]
But ... is there no other way to *compute* the actual size of the array
(here 96) *inside* the function without expecting to have it "pre-chewed" by
the calling routine?

No. Although you can write the parameter as if it were an
array, in truth it is a pointer to an element of the array. So
sizeof produces the size of a pointer, not the size of the thing
pointed to nor the size of the whole array of things.

See Question 6.21 -- in fact, most of Section 6 -- in the
comp.lang.c Frequently Asked Questions (FAQ) list

http://www.c-faq.com/

See also the rest of the FAQ; it's nutritious.

--
Eric.Sosman@xxxxxxx
.

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