Re: comma operator

Richard Heathfield <rjh@xxxxxxxxxxxxxxx> writes:
Keith Thompson said:
luserXtrog <mijoryx@xxxxxxxxx> writes:
[...]
I find it easier to think of the comma as a semicolon without
a period. It terminates the expression without terminating the
statement.

Ah, but it doesn't terminate the expression; it only terminates a
subexpression.

Yes, it does. An expression is "a sequence of operators and operands
that specifies computation of a value, or that designates an object
or a function, or that generates side effects, or that performs a
combination thereof". A comma operator always terminates such a
sequence.

You're right, of course. (The standard's definition of "expression"
is broken, but that's a separate point.)

Incidentally, that's true only because the comma operator has a lower
precedence than any other operator.

--
Keith Thompson (The_Other_Keith) kst-u@xxxxxxx <http://www.ghoti.net/~kst>
Nokia
"We must do something. This is something. Therefore, we must do this."
-- Antony Jay and Jonathan Lynn, "Yes Minister"
.

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