Re: determining size of array of chars

dehantonio <dehantonio@xxxxxxxxx>, on 23/08/2010 08:00:02, wrote:

On 23 Ago, 16:51, You're talkin 'bout China Blue Grove
<chine.b...@xxxxxxxxx> wrote:
This is an array of strings, not chars. A trick to get the length of an array A
is
(sizeof A/sizeof A[0])
provided A is actually an array and not a pointer.

In other words, it will not work with my code. Correct?
Said that, the answer is there is no way to get rid of the define in
my code?

It seems to work - caveat, I'm just starting with C, so cope with any error of mine (but point them out if any, please):

#include <stdlib.h>
#include <string.h>

const char *LineMenu[] = {"ls", "pwd", "cd"};

int somefunction(char* inputbuffer) {
int idx;

const int menusize = sizeof(LineMenu) / sizeof(LineMenu[0]);

for (idx = 0; idx < menusize; idx++) {
if (strstr(inputbuffer, LineMenu[idx])) {
return idx;
}
}
//not found:
return -1;
}

int main(void) {
printf("%d\n", somefunction("cd"));
return 0;
}



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