Re: is this typedef valid?

From: Ioannis Vranos (ivr_at_remove.this.grad.com)
Date: 02/17/05 

Date: Thu, 17 Feb 2005 04:45:04 +0200

lou zion wrote:

> hi all,
>
> i want to create a vector where each element is an array of 40 doubles. is
> this valid? something like:
>
> void abc( std::vector<double> InVals)
> {
> typedef double DataSeriesType[40];
> std::vector<DataSeriesType> DataSeriesX;
>
> DataSeriesType NewData;
> DataSeriesX.push_back(NewData);
>
> for (int i=0; i<(int)InVals.size(); i++) {
> DataSeriesX[0][i]=InVals[i];
> }
> }
>
> the above is not good code, i know, i'm just using it as an example of
> syntax, not style.
>
> essentially i want to store an array (or possibly a vector) in a vector. if
> i just store a pointer to an array in a vector, what happens if i delete
> that element? do i need to deallocate storage somehow? i'd prefer an array,
> but if there's a better way to do this, please enlighten.

#include <vector>

void abc(const std::vector<double> &InVals)
{
     using namespace std;

     vector<vector<double> >DataSeriesX;

     vector<double> NewData(40);

     DataSeriesX.push_back(NewData);

     for(vector<double>::size_type i=0; i<InVals.size(); ++i)
        DataSeriesX[0][i]=InVals[i];
}

or

#include <vector>

void abc(const std::vector<double> &InVals)
{
     using namespace std;

     typedef vector<double>DataSeriesType;

     vector<DataSeriesType> DataSeriesX;

     DataSeriesType NewData(40);

     DataSeriesX.push_back(NewData);

     for(vector<double>::size_type i=0; i<InVals.size(); ++i)
        DataSeriesX[0][i]=InVals[i];
} 

-- 
Ioannis Vranos
http://www23.brinkster.com/noicys

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