Re: Tough problem...

On Wed, 28 Jun 2006 08:00:40 +0200, "Avatar Zondertau"
<avatarzt@xxxxxxxxx (please reply to newsgroup)> wrote:

That won't work if arg has a fractional part.

Gah, I meant to say j:= j + arg; and use j directly, but somehow my
brain derailed...

- Asbjørn
.