Re: Fastcode CharPosIEx B&V 1.0.2

Hi

Now open the CPU view and observe that LStrLen is called once for every loop
iteration. The compiler should have been smart enough to observe that it is
loop invariant.

//while Index <= Length(S) do
mov eax,edi
call @LStrLen
cmp esi,eax
jle $0047a42c

We can code it like this

function CharPosIEx_NN_Pas_4_a(SearchChar : Char; const S: string; Offset:
Integer = 1) : Integer;
var
UpperSearchChar : Char;
Index, LengthS : Integer;

begin
Result := 0;
UpperSearchChar := UpCase_NN_Pas_1(SearchChar);
LengthS := Length(S);
Index := Offset;
if Index > 0 then
begin
while Index <= LengthS do
begin
if UpCase_NN_Pas_1(S[Index]) = UpperSearchChar then
begin
//We have a match
Result := Index;
Break;
end;
Inc(Index);
end;
end;
end;

Best regards
Dennis Kjaer Christensen

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