StringGrid.rows - out of bound problem after deleterow

From: Aramis Gunton (aramis_at_nink.demon.co.uk)
Date: 06/24/04

  • Next message: Maarten Wiltink: "Re: StringGrid.rows - out of bound problem after deleterow" 
    Date: Thu, 24 Jun 2004 12:36:01 +0100

    I have a TStringGrid that requires a delete row feature.

    I have used the grid hack to gain access to "deleterow" and "moverow"
    which indeed removes the selected row however subsequent to the deletion
    the row now occupying the deleted rows original position is
    inaccessible.

    StringGrid1.rows[deletedposition] returns ([(out of bound) 2, (out of
    bound) 4], #0. #0, 0 nil) as opposed to ([], #0, #0, 0, nil) for all of
    the other rows.

    I have an example that operates perfectly however I do not understand
    why on the sample TStringGrid evaluation of rows[index] = () whereas in
    my software the same expression yields ([],#0,#0, 0, nil)

    I just cannot get round this obstacle and fail to understand why I am
    experiencing the problem described when the sample I have which does
    ostensibly the same thing operates perfectly.

    Is there a simple reason why inside the Debug Inspector my
    StringGrid.row[0] has a "Data" element tab containing Fdefined,
    FDelimeter etc whereas in the working row deletion/insertion example I
    have StringGrid.row[0] does not.

    I assume I am missing the obvious here.

    Many thanks for any insight. 

    -- 
Aramis Gunton
  • Next message: Maarten Wiltink: "Re: StringGrid.rows - out of bound problem after deleterow"