Re: Have you tried recursion with Ackerman?
- From: "Maarten Wiltink" <maarten@xxxxxxxxxxxxxxxxxx>
- Date: Mon, 20 Nov 2006 10:07:22 +0100
"Heinrich Wolf" <invalid@xxxxxxxxxxxxxxx> wrote in message
news:ejpqu1$4r5$1@xxxxxxxxxxxxxxxxxxxxx
Ackerman(0, y) := y + 1;
Ackerman(x, 0) := Ackerman(x - 1, 1);
Ackerman(x, y) := Ackerman(x - 1, Ackerman(x, y - 1));
No. Why do you ask?
Groetjes,
Maarten Wiltink
.
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