Re: Initialisation of derived type array

Walter Spector <w6ws_xthisoutx@xxxxxxxxxxxxx> wrote:

David Flower wrote:
...
OK So far; but I want to initialise each array element to a different
value, and cannot find the syntax

I think you are looking for something like:

TYPE ( WRITE ) :: R(42) = (/ &
WRITE (1st set of values), &
WRITE (2nd set of values), &
...
WRITE (42nd set of values) &
/)

The main message I'd try to get across, again, is that there is no
special syntax for any of this stuff. You get this by putting together
the 3 pieces, namely:

1. The syntax of initialization in a type declaration, which is roughly
(omitting side matters)

type-specification :: object = value

All your questions are in essence about how to write a value.

2. To write a derived-type value, use a derived-type constructor,
as in

write(component-values)

This is not a syntax for writing a derived type value in
initialization. It is a syntax for writing a derived type value wherever
you happen to need one.

3. To write an array value, use an array constructor, as in

(/ list-of-values /)

or, using the f2003 brackets, supported by some current compilers,

[ list-of-values ]

This is not a syntax for writing array values in initialization. It is
a syntax for writing an array value wherever you happen to need one.
(And it has alternatives using implied DO, which are often handy).

Walter's example above just puts together those 3 parts.

--
Richard Maine | Good judgment comes from experience;
email: my first.last at org.domain| experience comes from bad judgment.
org: nasa, domain: gov | -- Mark Twain
.

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