Re: Is there any good nemerical methods to do Indefinite Integrals with fortran?

"Arjen Markus" <arjen.markus@xxxxxxxxxx> writes:

Nye schreef:

It's a bit off-topic, but I've searching for this for a long time,
thanks

--

Don't forget your dreamS

One method is to transform the integrand so that the bound is no longer
at
infinity. For instance:

inf 1
INT exp(-x) dx = INT exp(-y/(1-y)) d(y/(1-y) = ...
0 0

x = y/(1-y)

Then you can use any integration routine you like.

A general source of information is of course http://www.netlib.org

Regards,

Arjen

Thanks very much, your information's very incisive...
--

Don't forget your dreamS
.

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